What is the solution for xy^2y^'=y^3-3x^3 ?

The solution for xy^2y^'=y^3-3x^3 is y=x\sqrt[3]{-9ln(x)+c_{1}}

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xy^2y^'=y^3-3x^3

x y^{2} y^{^{'}} = y^{3} - 3 x^{3}

y = x 3 - 9 ln (x) + c_{1}

Solution steps

x y^{2} y^{'} (x) = y^{3} - 3 x^{3}

Solve Bernoulli ODE:

y = x 3 - 9 ln (x) + c_{1}

y = x 3 - 9 ln (x) + c_{1}

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What is the solution for xy^2y^'=y^3-3x^3 ?
The solution for xy^2y^'=y^3-3x^3 is y=x\sqrt[3]{-9ln(x)+c_{1}}