What is the tangent of f(x)=(4x)/(x+2),(2,2) ?

The tangent of f(x)=(4x)/(x+2),(2,2) is y= 1/2 x+1

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tangent of f(x)=(4x)/(x+2),(2,2)

tangent of

f (x) = \frac{4 x}{x + 2}, (2, 2)

y = \frac{1}{2} x + 1

Solution steps

Find the slope of

f (x) = \frac{4 x}{x + 2} : \frac{df ( x )}{d x} = \frac{8}{( x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(2, 2) : y = \frac{1}{2} x + 1

y = \frac{1}{2} x + 1

\frac{\partial}{\partial x} (\frac{2 x + 2}{y ^{3}})

\frac{d}{d x} (5 x^{3} 25 - x^{2})

\frac{d y}{d x} = \frac{y - 1}{x ^{2}}

\int x cos (x y) + 1 d y

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What is the tangent of f(x)=(4x)/(x+2),(2,2) ?
The tangent of f(x)=(4x)/(x+2),(2,2) is y= 1/2 x+1