What is the d/(dt)(4cos(pit)) ?

The d/(dt)(4cos(pit)) is -4pisin(pit)

What is the first d/(dt)(4cos(pit)) ?

The first d/(dt)(4cos(pit)) is -4pisin(pit)

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\frac{d}{d t} (4 cos (π t))

- 4 π sin (π t)

Solution steps

\frac{d}{d t} (4 cos (π t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (cos (π t))

Apply the chain rule:

- sin (π t) \frac{d}{d t} (π t)

= - sin (π t) \frac{d}{d t} (π t)

\frac{d}{d t} (π t) = π

= 4 (- sin (π t) π)

Simplify

= - 4 π sin (π t)

(sin (π))^{^{'}}

\frac{d}{d x} (2^{t a n (x)})

\int_{1}^{2} 2 (x - 1) d x

\int \frac{x ^{2}}{4 + x ^{2}} d x

\int \frac{x ^{4} + 1}{x ^{3} - x ^{2} + x - 1} d x

What is the d/(dt)(4cos(pit)) ?
The d/(dt)(4cos(pit)) is -4pisin(pit)
What is the first d/(dt)(4cos(pit)) ?
The first d/(dt)(4cos(pit)) is -4pisin(pit)