What is the derivative of f(1)=9+3/x ?

The derivative of f(1)=9+3/x is -3/(x^2)

What is the first derivative of f(1)=9+3/x ?

The first derivative of f(1)=9+3/x is -3/(x^2)

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derivative of

f (1) = 9 + \frac{3}{x}

- \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (9 + \frac{3}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) + \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (9) = 0

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= 0 - \frac{3}{x ^{2}}

Simplify

= - \frac{3}{x ^{2}}

f (x) = 3 x + 8

\frac{d}{d x} (\frac{4 - x ^{2}}{3 x - 2})

y^{^{'}} = \frac{- 1}{x ^{2}}

n = 0 \sum \infty \frac{1}{5} \cdot (- \frac{2}{3})^{n}

x^{2} + y^{2} = 25, (- 4, 3)

What is the derivative of f(1)=9+3/x ?
The derivative of f(1)=9+3/x is -3/(x^2)
What is the first derivative of f(1)=9+3/x ?
The first derivative of f(1)=9+3/x is -3/(x^2)