What is laplacetransform e^{-2t+3} ?

The answer to laplacetransform e^{-2t+3} is (e^3)/(s+2)

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laplacetransform e^{-2t+3}

laplace transform

e^{- 2 t + 3}

\frac{e ^{3}}{s + 2}

Solution steps

L {e^{- 2 t + 3}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{3} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{3} \frac{1}{s + 2}

Refine

e^{3} \frac{1}{s + 2} : \frac{e ^{3}}{s + 2}

= \frac{e ^{3}}{s + 2}

\int \frac{4}{θ ^{2}} cos (\frac{4}{θ}) d θ

\int \frac{1}{x ( x - 4 )} d x

f (x) = \frac{2 t}{2 t}

y^{^{''}} - 2 y^{^{'}} + y = \frac{( e ^{x} )}{1 + x ^{2}}

\frac{d}{d t} (1 - t^{2})

What is laplacetransform e^{-2t+3} ?
The answer to laplacetransform e^{-2t+3} is (e^3)/(s+2)