What is (\partial)/(\partial y)(x^2yz^2) ?

The answer to (\partial)/(\partial y)(x^2yz^2) is x^2z^2

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(\partial)/(\partial y)(x^2yz^2)

\frac{\partial}{\partial y} (x^{2} y z^{2})

x^{2} z^{2}

Solution steps

\frac{\partial}{\partial y} (x^{2} y z^{2})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} z^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x^{2} z^{2} \cdot 1

Simplify

= x^{2} z^{2}

\int_{5}^{\infty} \frac{1}{x ^{3}} d x

\frac{\partial}{\partial x} (1 - ln (x))

\int_{1}^{3} x \frac{2.25}{x ^{3}} d x

y^{^{''}} + 10 y^{^{'}} + 21 y = 0, y (0) = 10, y^{^{'}} (0) = - 42

x \to \infty lim (x^{4 x})

What is (\partial)/(\partial y)(x^2yz^2) ?
The answer to (\partial)/(\partial y)(x^2yz^2) is x^2z^2