What is the integral of 2x^5-7x^3+6 ?

The integral of 2x^5-7x^3+6 is (x^6)/3-(7x^4)/4+6x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2x^5-7x^3+6

\int 2 x^{5} - 7 x^{3} + 6 d x

\frac{x ^{6}}{3} - \frac{7 x ^{4}}{4} + 6 x + C

Solution steps

\int 2 x^{5} - 7 x^{3} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{5} d x - \int 7 x^{3} d x + \int 6 d x

\int 2 x^{5} d x = \frac{x ^{6}}{3}

\int 7 x^{3} d x = \frac{7 x ^{4}}{4}

\int 6 d x = 6 x

= \frac{x ^{6}}{3} - \frac{7 x ^{4}}{4} + 6 x

Add a constant to the solution

= \frac{x ^{6}}{3} - \frac{7 x ^{4}}{4} + 6 x + C

\frac{d}{d x} ((9 - x^{2})^{\frac{2}{3}})

\int x x - 5 d x

\frac{\partial}{\partial x} (x^{2} y + ln (x))

7 x^{2} - 3 x, x^{2} - 7 x + 2

x \to + 0 + lim (\frac{e ^{x}}{e ^{x} - 1})

What is the integral of 2x^5-7x^3+6 ?
The integral of 2x^5-7x^3+6 is (x^6)/3-(7x^4)/4+6x+C