What is the tangent of f(x)=2x^2-3x-2,\at x=6 ?

The tangent of f(x)=2x^2-3x-2,\at x=6 is y=21x-74

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tangent of f(x)=2x^2-3x-2,\at x=6

tangent of

f (x) = 2 x^{2} - 3 x - 2, at x = 6

y = 21 x - 74

Solution steps

Find the tangent point:

(6, 52)

Find the slope of

f (x) = 2 x^{2} - 3 x - 2 : \frac{df ( x )}{d x} = 4 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 21

Find the line with slope m=

21

and passing through

(6, 52) : y = 21 x - 74

y = 21 x - 74

\int_{- \infty}^{- 1} e^{- 4 t} d t

f (x) = (x^{2} - 4) (3 x + 1)

f (x) = \frac{( e ^{x} )}{7 x ^{2} + 1}

\int x^{3} 2 x^{4} + 3 d x

\frac{\partial}{\partial r} (r ln (r^{2} + s^{2}))

What is the tangent of f(x)=2x^2-3x-2,\at x=6 ?
The tangent of f(x)=2x^2-3x-2,\at x=6 is y=21x-74