What is the solution for y^'-3y=4e^{5t},y(0)=5 ?

The solution for y^'-3y=4e^{5t},y(0)=5 is y=2e^{5t}+3e^{3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-3y=4e^{5t},y(0)=5

y^{^{'}} - 3 y = 4 e^{5 t}, y (0) = 5

y = 2 e^{5 t} + 3 e^{3 t}

Solution steps

y^{'} (t) - 3 y = 4 e^{5 t}

Solve linear ODE:

y = 2 e^{5 t} + 3 e^{3 t}

y = 2 e^{5 t} + 3 e^{3 t}

y - x \frac{d y}{d x} = 3 - 2 x^{2} \frac{d y}{d x}

\int \frac{1}{x ( x - 8 ) ^{2}} d x

\frac{d}{d x} (π x^{2} y)

\int_{0}^{1} ln (9 x) d x

\int 7 x + 2 d x

What is the solution for y^'-3y=4e^{5t},y(0)=5 ?
The solution for y^'-3y=4e^{5t},y(0)=5 is y=2e^{5t}+3e^{3t}