What is the solution for (dy)/(dx)=y(y+1)x ?

The solution for (dy)/(dx)=y(y+1)x is y=(e^{(x^2)/2+c_{1}})/(1-e^{(x^2)/2+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=y(y+1)x

\frac{d y}{d x} = y (y + 1) x

y = \frac{e ^{\frac{x ^{2}}{2} + c_{1}}}{1 - e ^{\frac{x ^{2}}{2} + c_{1}}}

Solution steps

\frac{d y}{d x} = y (y + 1) x

Solve separable ODE:

y = \frac{e ^{\frac{x ^{2}}{2} + c_{1}}}{1 - e ^{\frac{x ^{2}}{2} + c_{1}}}

y = \frac{e ^{\frac{x ^{2}}{2} + c_{1}}}{1 - e ^{\frac{x ^{2}}{2} + c_{1}}}

x \to 3 + lim (\frac{x - 3}{x - 3})

\frac{d}{d x} (ln (12 - 9 x^{2} + 2 x^{4}))

30 e^{- x^{\frac{2}{3}}}

y = arcsin (x)

y = (x^{2} + 3 x - 2)^{4}

What is the solution for (dy)/(dx)=y(y+1)x ?
The solution for (dy)/(dx)=y(y+1)x is y=(e^{(x^2)/2+c_{1}})/(1-e^{(x^2)/2+c_{1)}}