What is the integral from 2 to e^5 of 1/x ?

The integral from 2 to e^5 of 1/x is 5-ln(2)

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integral from 2 to e^5 of 1/x

\int_{2}^{e^{5}} \frac{1}{x} d x

5 - ln (2)

Solution steps

\int_{2}^{e^{5}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{2}^{e^{5}}

Compute the boundaries:

5 - ln (2)

= 5 - ln (2)

\int cos^{5} (x s i) n^{2} x d x

f (x) = 2 + e^{x}, at x = 1

x \to 2 lim (- x^{2} + 3 x)

\int \frac{3 x ^{2} + 6 x + 2}{x ^{2} + 3 x + 2} d x

\frac{d}{d x} (\frac{5}{x ^{2} + 1})

What is the integral from 2 to e^5 of 1/x ?
The integral from 2 to e^5 of 1/x is 5-ln(2)