What is the derivative of y=2(x^2-7x)(2x-7) ?

The derivative of y=2(x^2-7x)(2x-7) is 2(6x^2-42x+49)

What is the first derivative of y=2(x^2-7x)(2x-7) ?

The first derivative of y=2(x^2-7x)(2x-7) is 2(6x^2-42x+49)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 2 (x^{2} - 7 x) (2 x - 7)

2 (6 x^{2} - 42 x + 49)

Solution steps

\frac{d}{d x} (2 (x^{2} - 7 x) (2 x - 7))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((x^{2} - 7 x) (2 x - 7))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} - 7 x, g = 2 x - 7

= 2 (\frac{d}{d x} (x^{2} - 7 x) (2 x - 7) + \frac{d}{d x} (2 x - 7) (x^{2} - 7 x))

\frac{d}{d x} (x^{2} - 7 x) = 2 x - 7

\frac{d}{d x} (2 x - 7) = 2

= 2 ((2 x - 7) (2 x - 7) + 2 (x^{2} - 7 x))

Simplify

2 ((2 x - 7) (2 x - 7) + 2 (x^{2} - 7 x)) : 2 (6 x^{2} - 42 x + 49)

= 2 (6 x^{2} - 42 x + 49)

\int cos (x) csc^{9} (x) d x

x^{3} y^{^{'''}} + 6 y = 0

\int 4 sin (θ) d θ

x \to 1 lim (3 x^{3} - 4 x^{2} + x + 9)

x \to 1 - lim (x^{3} + 1)

What is the derivative of y=2(x^2-7x)(2x-7) ?
The derivative of y=2(x^2-7x)(2x-7) is 2(6x^2-42x+49)
What is the first derivative of y=2(x^2-7x)(2x-7) ?
The first derivative of y=2(x^2-7x)(2x-7) is 2(6x^2-42x+49)