What is the integral of e^{-u^2} ?

The integral of e^{-u^2} is (sqrt(pi))/2 \erf(u)+C

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integral of e^{-u^2}

\int e^{- u^{2}} d u

\frac{π}{2} erf (u) + C

Solution steps

\int e^{- u^{2}} d u

Use the nonelementary integral:

\int e^{- u^{2}} d u = \frac{π}{2} erf (u)

= \frac{π}{2} erf (u)

Add a constant to the solution

= \frac{π}{2} erf (u) + C

n = 1 \sum \infty (\frac{7}{8})^{n - 1}

\frac{d}{d x} (e^{\frac{x}{x - 8}})

\int (9 x^{2} - 8 x) e^{2 x} d x

y^{^{''}} - 6 y + 9 y = 0

\frac{d y}{d x} = \frac{( 2 x ^{2} + 3 ) ( 3 x + 2 )}{7 x - 3}

What is the integral of e^{-u^2} ?
The integral of e^{-u^2} is (sqrt(pi))/2 \erf(u)+C