What is the derivative of 2ax+b/x ?

The derivative of 2ax+b/x is 2a-b/(x^2)

What is the first derivative of 2ax+b/x ?

The first derivative of 2ax+b/x is 2a-b/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

2 a x + \frac{b}{x}

2 a - \frac{b}{x ^{2}}

Solution steps

\frac{d}{d x} (2 a x + \frac{b}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 a x) + \frac{d}{d x} (\frac{b}{x})

\frac{d}{d x} (2 a x) = 2 a

\frac{d}{d x} (\frac{b}{x}) = - \frac{b}{x ^{2}}

= 2 a - \frac{b}{x ^{2}}

\frac{d}{d x} (arctan (\frac{13}{x}) - arctan (\frac{3}{x}))

\frac{\partial}{\partial x} (x e^{y^{2}} - y e^{x^{2}})

\frac{d}{d x} (e^{2 x} - x^{2} - 1)

x \to 4 lim (4 - x)

\int csc (- 4 x) d x

What is the derivative of 2ax+b/x ?
The derivative of 2ax+b/x is 2a-b/(x^2)
What is the first derivative of 2ax+b/x ?
The first derivative of 2ax+b/x is 2a-b/(x^2)