What is the derivative of f(x)=x^2-2cos(x)-3 ?

The derivative of f(x)=x^2-2cos(x)-3 is 2x+2sin(x)

What is the first derivative of f(x)=x^2-2cos(x)-3 ?

The first derivative of f(x)=x^2-2cos(x)-3 is 2x+2sin(x)

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derivative of

f (x) = x^{2} - 2 cos (x) - 3

2 x + 2 sin (x)

Solution steps

\frac{d}{d x} (x^{2} - 2 cos (x) - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 cos (x)) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (3) = 0

= 2 x - (- 2 sin (x)) - 0

Simplify

= 2 x + 2 sin (x)

x y^{2} y^{^{'}} = y^{3} - x^{3}

\int \frac{( 1 )}{25 x ^{2} - 16} d x

\int \frac{4 x}{2 x ^{2} + 1} d x

\frac{d y}{d x} + 6 y = e^{x}

\int x^{3} + x^{\frac{1}{3}} d x

What is the derivative of f(x)=x^2-2cos(x)-3 ?
The derivative of f(x)=x^2-2cos(x)-3 is 2x+2sin(x)
What is the first derivative of f(x)=x^2-2cos(x)-3 ?
The first derivative of f(x)=x^2-2cos(x)-3 is 2x+2sin(x)