What is the solution for (2x+3y)dx+(6x+9y-3)dy=0 ?

The solution for (2x+3y)dx+(6x+9y-3)dy=0 is y=-(2x)/3+(\W(1/(3e^{(-3x-c_{1))/3}}))/(3)+2/3

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(2x+3y)dx+(6x+9y-3)dy=0

(2 x + 3 y) d x + (6 x + 9 y - 3) d y = 0

y = - \frac{2 x}{3} + \frac{W ( \frac{1}{3 e ^{\frac{- 3 x - c _{1}}{3}}} )}{3} + \frac{2}{3}

Solution steps

(2 x + 3 y) d x + (6 x + 9 y - 3) d y = 0

Solve using substitution:

y = - \frac{2 x}{3} + \frac{W ( \frac{1}{3 e ^{\frac{- 3 x - c _{1}}{3}}} )}{3} + \frac{2}{3}

y = - \frac{2 x}{3} + \frac{W ( \frac{1}{3 e ^{\frac{- 3 x - c _{1}}{3}}} )}{3} + \frac{2}{3}

\int d (x y)

\frac{\partial}{\partial y} (y^{3} + 2 y e^{x})

\frac{\partial}{\partial x} (2 x^{3} y + cos (x^{3}))

\frac{\partial}{\partial y} (\frac{100}{5 x ^{2} + y ^{2}})

\frac{s}{s ^{2} + 4 s}

What is the solution for (2x+3y)dx+(6x+9y-3)dy=0 ?
The solution for (2x+3y)dx+(6x+9y-3)dy=0 is y=-(2x)/3+(\W(1/(3e^{(-3x-c_{1))/3}}))/(3)+2/3