What is the derivative of 1-x^{3/2} ?

The derivative of 1-x^{3/2} is -(3x^{1/2})/2

What is the first derivative of 1-x^{3/2} ?

The first derivative of 1-x^{3/2} is -(3x^{1/2})/2

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\frac{d}{d x} (1 - x^{\frac{3}{2}})

- \frac{3 x ^{\frac{1}{2}}}{2}

Solution steps

\frac{d}{d x} (1 - x^{\frac{3}{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (x^{\frac{3}{2}})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{\frac{3}{2}}) = \frac{3 x ^{\frac{1}{2}}}{2}

= 0 - \frac{3 x ^{\frac{1}{2}}}{2}

Simplify

= - \frac{3 x ^{\frac{1}{2}}}{2}

\int (2 x + 3)^{3} d x

\frac{d}{d x} (\frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7)

f^{^{'}} (x) = e^{- 2 x}

\frac{d}{d x} (\frac{2 x + sin ( x )}{2 x + cos ( x )})

(1, 10), (24, - 26)

What is the derivative of 1-x^{3/2} ?
The derivative of 1-x^{3/2} is -(3x^{1/2})/2
What is the first derivative of 1-x^{3/2} ?
The first derivative of 1-x^{3/2} is -(3x^{1/2})/2