What is the solution for (dy)/(dx)=(y-1-2y+y+1)/(x^2) ?

The solution for (dy)/(dx)=(y-1-2y+y+1)/(x^2) is y=c_{1}

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(dy)/(dx)=(y-1-2y+y+1)/(x^2)

\frac{d y}{d x} = \frac{y - 1 - 2 y + y + 1}{x ^{2}}

y = c_{1}

Solution steps

\frac{d y}{d x} = \frac{y - 1 - 2 y + y + 1}{x ^{2}}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{y - 1 - 2 y + y + 1}{x ^{2}}

Simplify

y^{^{'}} (x) = 0

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 0 d x

\int 0 d x = c_{1}

y = c_{1}

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x \to + 1 lim (ln (x))

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6 x, \frac{2}{3} x, 40 - x^{2}

What is the solution for (dy)/(dx)=(y-1-2y+y+1)/(x^2) ?
The solution for (dy)/(dx)=(y-1-2y+y+1)/(x^2) is y=c_{1}