What is the solution for y^'+4xy=xe^{x^2} ?

The solution for y^'+4xy=xe^{x^2} is y=(e^{x^2})/6+(c_{1})/(e^{2x^2)}

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y^'+4xy=xe^{x^2}

y^{^{'}} + 4 x y = x e^{x^{2}}

y = \frac{e ^{x^{2}}}{6} + \frac{c _{1}}{e ^{2 x^{2}}}

Solution steps

y^{'} (x) + 4 x y = x e^{x^{2}}

Solve linear ODE:

y = \frac{e ^{x^{2}}}{6} + \frac{c _{1}}{e ^{2 x^{2}}}

y = \frac{e ^{x^{2}}}{6} + \frac{c _{1}}{e ^{2 x^{2}}}

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What is the solution for y^'+4xy=xe^{x^2} ?
The solution for y^'+4xy=xe^{x^2} is y=(e^{x^2})/6+(c_{1})/(e^{2x^2)}