What is the solution for (dy}{dx}=\frac{(-xe^{-x^2}))/y ?

The solution for (dy}{dx}=\frac{(-xe^{-x^2}))/y is y=sqrt(e^{-x^2)+c_{1}},y=-sqrt(e^{-x^2)+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{(-xe^{-x^2}))/y

\frac{d y}{d x} = \frac{( - x e ^{- x^{2}} )}{y}

y = e^{- x^{2}} + c_{1}, y = - e^{- x^{2}} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( - x e ^{- x^{2}} )}{y}

Solve separable ODE:

y = e^{- x^{2}} + c_{1}, y = - e^{- x^{2}} + c_{1}

y = e^{- x^{2}} + c_{1}, y = - e^{- x^{2}} + c_{1}

\int 8 x^{2} cos (2 x) d x

\int (x^{2} + 1)^{3} \cdot x d x

n = 1 \sum \infty (\frac{1}{n}) (\frac{1}{n})^{2}

y^{^{'}} = \frac{2 x y}{x ^{2} + 1}

f (x) = 6 + 1 - x, at x = - 8

What is the solution for (dy}{dx}=\frac{(-xe^{-x^2}))/y ?
The solution for (dy}{dx}=\frac{(-xe^{-x^2}))/y is y=sqrt(e^{-x^2)+c_{1}},y=-sqrt(e^{-x^2)+c_{1}}