What is the solution for x(dy)/(dx)+3x^2+4y=0 ?

The solution for x(dy)/(dx)+3x^2+4y=0 is y=-(x^2)/2+(c_{1})/(x^4)

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x(dy)/(dx)+3x^2+4y=0

x \frac{d y}{d x} + 3 x^{2} + 4 y = 0

y = - \frac{x ^{2}}{2} + \frac{c _{1}}{x ^{4}}

Solution steps

x \frac{d y}{d x} + 3 x^{2} + 4 y = 0

Solve linear ODE:

y = - \frac{x ^{2}}{2} + \frac{c _{1}}{x ^{4}}

y = - \frac{x ^{2}}{2} + \frac{c _{1}}{x ^{4}}

x \cdot e^{x}

x (x^{3} + 8)

\frac{2 x - 6}{x - 6}

\int \frac{\frac{1}{x}}{ln ( x )} d x

\frac{e ^{- x}}{1 + e ^{- x}}

What is the solution for x(dy)/(dx)+3x^2+4y=0 ?
The solution for x(dy)/(dx)+3x^2+4y=0 is y=-(x^2)/2+(c_{1})/(x^4)