What is the derivative of f(x)=e^x-cot(x) ?

The derivative of f(x)=e^x-cot(x) is e^x+csc^2(x)

What is the first derivative of f(x)=e^x-cot(x) ?

The first derivative of f(x)=e^x-cot(x) is e^x+csc^2(x)

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derivative of

f (x) = e^{x} - cot (x)

e^{x} + csc^{2} (x)

Solution steps

\frac{d}{d x} (e^{x} - cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (cot (x))

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= e^{x} - (- csc^{2} (x))

Simplify

= e^{x} + csc^{2} (x)

\frac{d}{d x} (x sin (x^{3}))

\int_{- 1}^{5} (y^{2} - 5) - 4 y d y

\int_{0}^{2} 20000 e^{0.03 x} d x

k = 1 \sum \infty k \cdot 2^{- k}

h \to 0 lim (- 8 p - 4 h - 7)

What is the derivative of f(x)=e^x-cot(x) ?
The derivative of f(x)=e^x-cot(x) is e^x+csc^2(x)
What is the first derivative of f(x)=e^x-cot(x) ?
The first derivative of f(x)=e^x-cot(x) is e^x+csc^2(x)