What is the derivative of 4x^{-1} ?

The derivative of 4x^{-1} is -4/(x^2)

What is the first derivative of 4x^{-1} ?

The first derivative of 4x^{-1} is -4/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

4 x^{- 1}

- \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (4 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 1 \cdot x^{- 1 - 1})

Simplify

4 (- 1 \cdot x^{- 1 - 1}) : - \frac{4}{x ^{2}}

= - \frac{4}{x ^{2}}

\frac{\partial}{\partial y} (x^{2} - 4 y^{2})

(0, - 2), (- \frac{1}{2}, 3)

n = 5 \sum \infty \frac{1}{n ( n + 1 )}

\frac{d y}{d x} = sin (5 x)

\int 5 x - 1 d x

What is the derivative of 4x^{-1} ?
The derivative of 4x^{-1} is -4/(x^2)
What is the first derivative of 4x^{-1} ?
The first derivative of 4x^{-1} is -4/(x^2)