What is (\partial)/(\partial y)(sqrt(2x+y)) ?

The answer to (\partial)/(\partial y)(sqrt(2x+y)) is 1/(2sqrt(2x+y))

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(\partial)/(\partial y)(sqrt(2x+y))

\frac{\partial}{\partial y} (2 x + y)

\frac{1}{2 2 x + y}

Solution steps

\frac{\partial}{\partial y} (2 x + y)

Treat

x

as a constant

Apply the chain rule:

\frac{1}{2 2 x + y} \frac{\partial}{\partial y} (2 x + y)

= \frac{1}{2 2 x + y} \frac{\partial}{\partial y} (2 x + y)

\frac{\partial}{\partial y} (2 x + y) = 1

= \frac{1}{2 2 x + y} \cdot 1

Simplify

= \frac{1}{2 2 x + y}

\frac{\partial}{\partial x} (40 x y^{- 4} z)

\int_{- 2}^{2} (4 - x^{2})^{2} d x

\frac{d}{d x} ((5 x - 3)^{4} (2 x - 7)^{- 3})

(\frac{1}{2 x})^{^{'}}

θ cos (θ)

What is (\partial)/(\partial y)(sqrt(2x+y)) ?
The answer to (\partial)/(\partial y)(sqrt(2x+y)) is 1/(2sqrt(2x+y))