What is (\partial)/(\partial x)(4x^3y^2+4) ?

The answer to (\partial)/(\partial x)(4x^3y^2+4) is 12x^2y^2

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(\partial)/(\partial x)(4x^3y^2+4)

\frac{\partial}{\partial x} (4 x^{3} y^{2} + 4)

12 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (4 x^{3} y^{2} + 4)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{3} y^{2}) + \frac{\partial}{\partial x} (4)

\frac{\partial}{\partial x} (4 x^{3} y^{2}) = 12 y^{2} x^{2}

\frac{\partial}{\partial x} (4) = 0

= 12 y^{2} x^{2} + 0

Simplify

= 12 x^{2} y^{2}

f (x) = 3 x^{4}

\frac{8}{s ^{3} ( s + 2 )}

4 - x^{2}, (- 2, 2)

\frac{7}{2 7 x + 2}

f (x) = 3 x^{- 4}

What is (\partial)/(\partial x)(4x^3y^2+4) ?
The answer to (\partial)/(\partial x)(4x^3y^2+4) is 12x^2y^2