What is (\partial)/(\partial y)(cos(y)sin(x)) ?

The answer to (\partial)/(\partial y)(cos(y)sin(x)) is -sin(y)sin(x)

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(\partial)/(\partial y)(cos(y)sin(x))

\frac{\partial}{\partial y} (cos (y) sin (x))

- sin (y) sin (x)

Solution steps

\frac{\partial}{\partial y} (cos (y) sin (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= sin (x) (- sin (y))

Simplify

= - sin (y) sin (x)

(- 3 t^{2}) (t - 2)

25 x^{3} - 6 x^{2} + 7 x - 88

\int \frac{8 x ^{2}}{( 64 + x ^{2} ) ^{2}} d x

(2.6) (4.12)

\int_{1}^{e^{6}} \frac{ln ^{2} ( x ^{2} )}{x} d x

What is (\partial)/(\partial y)(cos(y)sin(x)) ?
The answer to (\partial)/(\partial y)(cos(y)sin(x)) is -sin(y)sin(x)