What is area x=sqrt(25-y)-5,x=y-10 ?

The answer to area x=sqrt(25-y)-5,x=y-10 is 243/2

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area x=sqrt(25-y)-5,x=y-10

area

x = 25 - y - 5, x = y - 10

\frac{243}{2}

Decimal

121.5

Solution steps

Isolate

y

for

x = 25 - y - 5 : y = - x^{2} - 10 x {x \geq - 5}

Isolate

y

for

x = y - 10 : y = x + 10

Apply the area formula:

\int_{- 10}^{- 1} x^{2} + 11 x + 10 d x

Solve

\int_{- 10}^{- 1} x^{2} + 11 x + 10 d x : \frac{243}{2}

The area is:

= \frac{243}{2}

\frac{d}{d x} ((x^{2} - 4)^{2})

\frac{d}{d x} (2 π x (cos (π x^{2})))

y = x^{5} e^{x}

n = 1 \sum \infty 4

n = 1 \sum \infty 0. 2^{n}

What is area x=sqrt(25-y)-5,x=y-10 ?
The answer to area x=sqrt(25-y)-5,x=y-10 is 243/2