What is (\partial)/(\partial z)(-3xysin(z)) ?

The answer to (\partial)/(\partial z)(-3xysin(z)) is -3xycos(z)

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(\partial)/(\partial z)(-3xysin(z))

\frac{\partial}{\partial z} (- 3 x y sin (z))

- 3 x y cos (z)

Solution steps

\frac{\partial}{\partial z} (- 3 x y sin (z))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 x y \frac{\partial}{\partial z} (sin (z))

Apply the common derivative:

\frac{\partial}{\partial z} (sin (z)) = cos (z)

= - 3 x y cos (z)

f (x) = x^{2} + 5 x

x \to \infty lim (\frac{e ^{\frac{2}{x}} sin ( π x )}{x + 2} + x)

\frac{d}{d x} (6 x^{- 5})

x \to \infty + lim (x^{4})

\int (7 + x + x^{2}) d x

What is (\partial)/(\partial z)(-3xysin(z)) ?
The answer to (\partial)/(\partial z)(-3xysin(z)) is -3xycos(z)