What is the integral from 0 to pi of pisin^4(x) ?

The integral from 0 to pi of pisin^4(x) is (3pi^2)/8

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integral from 0 to pi of pisin^4(x)

\int_{0}^{π} π sin^{4} (x) d x

\frac{3 π ^{2}}{8}

Decimal

3.70110 \dots

Solution steps

\int_{0}^{π} π sin^{4} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{π} sin^{4} (x) d x

Apply Integral Reduction

= π (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \int_{0}^{π} sin^{2} (x) d x)

\int_{0}^{π} sin^{2} (x) d x = \frac{π}{2}

= π (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \frac{π}{2})

Simplify

π (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \frac{π}{2}) : π (- [\frac{1}{4} sin^{3} (x) cos (x)]_{0}^{π} + \frac{3 π}{8})

= π (- [\frac{1}{4} sin^{3} (x) cos (x)]_{0}^{π} + \frac{3 π}{8})

Compute the boundaries:

0

= π (- 0 + \frac{3 π}{8})

Simplify

= \frac{3 π ^{2}}{8}

x \to 2 lim (4)

\int (x + 4) (x - 5) d x

\frac{d}{d x} (- x^{2} - 1)

\frac{d}{d x} (\frac{x - 1}{x + 1})

(x^{2} - 7 x + 8) 25 - x^{2}

What is the integral from 0 to pi of pisin^4(x) ?
The integral from 0 to pi of pisin^4(x) is (3pi^2)/8