What is laplacetransform t^3*e^{-3t} ?

The answer to laplacetransform t^3*e^{-3t} is 6/((s+3)^4)

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laplacetransform t^3*e^{-3t}

laplace transform

t^{3} \cdot e^{- 3 t}

\frac{6}{( s + 3 ) ^{4}}

Solution steps

L {e^{- 3 t} t^{3}}

Use Laplace Transform table:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

For

t^{3} e^{- 3 t} : f (t) = e^{- 3 t}, k = 3

= (- 1)^{3} \frac{d ^{3}}{d s ^{3}} (L {e^{- 3 t}})

L {e^{- 3 t}} : \frac{1}{s + 3}

\frac{d ^{3}}{d s ^{3}} (\frac{1}{s + 3}) = - \frac{6}{( s + 3 ) ^{4}}

= (- 1)^{3} (- \frac{6}{( s + 3 ) ^{4}})

= \frac{6}{( s + 3 ) ^{4}}

\int 5 e^{- 3 x} d x

\frac{9 - x e ^{x}}{x + e ^{x}}

n = 1 \sum \infty ln (cos (n))

a cos (t) + t^{2} sin (t)

\int_{0}^{2} \frac{1}{( x - 1 ) ^{\frac{2}{3}}} d x

What is laplacetransform t^3*e^{-3t} ?
The answer to laplacetransform t^3*e^{-3t} is 6/((s+3)^4)