What is the d/(dt)(-8cos(t)) ?

The d/(dt)(-8cos(t)) is 8sin(t)

What is the first d/(dt)(-8cos(t)) ?

The first d/(dt)(-8cos(t)) is 8sin(t)

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\frac{d}{d t} (- 8 cos (t))

8 sin (t)

Solution steps

\frac{d}{d t} (- 8 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= - 8 (- sin (t))

Simplify

= 8 sin (t)

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