What is the tangent of f(x)=sqrt(2x),(8,4) ?

The tangent of f(x)=sqrt(2x),(8,4) is y= 1/4 x+2

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tangent of f(x)=sqrt(2x),(8,4)

tangent of

f (x) = 2 x, (8, 4)

y = \frac{1}{4} x + 2

Solution steps

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(8, 4) : y = \frac{1}{4} x + 2

y = \frac{1}{4} x + 2

\frac{\partial}{\partial x} (x^{6} y - 4 x^{5} y^{2})

e^{3 x} - e^{2 x}

\int - \frac{e ^{- 2 x}}{2} 2 d x

\int n e^{- n y} sin (n x) d x

x e^{x^{3}}

What is the tangent of f(x)=sqrt(2x),(8,4) ?
The tangent of f(x)=sqrt(2x),(8,4) is y= 1/4 x+2