What is the sum from n=1 to infinity of (n-1)/(2n+1) ?

The sum from n=1 to infinity of (n-1)/(2n+1) is diverges

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sum from n=1 to infinity of (n-1)/(2n+1)

n = 1 \sum \infty \frac{n - 1}{2 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 1}{2 n + 1}

Apply Series Divergence Test:

diverges

= diverges

cos (x^{- 9})

\frac{d}{d x} (3 - \frac{7}{2 x ^{\frac{1}{8}}})

x^{2} + y^{2} = 4, x^{2} + y^{2} = 4 x

\frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{5})

\int \frac{( x ^{2} + 1 - 2 x ) ^{\frac{1}{5}}}{1 - x} d x

What is the sum from n=1 to infinity of (n-1)/(2n+1) ?
The sum from n=1 to infinity of (n-1)/(2n+1) is diverges