What is the sum from n=0 to infinity of ((-6+7)/2)^n ?

The sum from n=0 to infinity of ((-6+7)/2)^n is 2

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sum from n=0 to infinity of ((-6+7)/2)^n

n = 0 \sum \infty (\frac{- 6 + 7}{2})^{n}

2

Solution steps

n = 0 \sum \infty (\frac{- 6 + 7}{2})^{n}

Simplify

= n = 0 \sum \infty (\frac{1}{2})^{n}

Apply Series Geometric Test:

2

= 2

g (x) = - x^{2} + 4 x^{2} - 2 x + 2

x^{2} - 4 x, 2 x + 7

\int cos (x) + \frac{1}{9} x d x

\int_{0}^{5} \frac{x}{9 - x} d x

y = 4 - x^{2}, y = - x + 2

What is the sum from n=0 to infinity of ((-6+7)/2)^n ?
The sum from n=0 to infinity of ((-6+7)/2)^n is 2