What is the derivative of-2/(x^3+3/(x^2)-4x) ?

The derivative of-2/(x^3+3/(x^2)-4x) is 6/(x^4)-6/(x^3)-4

What is the first derivative of-2/(x^3+3/(x^2)-4x) ?

The first derivative of-2/(x^3+3/(x^2)-4x) is 6/(x^4)-6/(x^3)-4

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\frac{d}{d x} (- \frac{2}{x ^{3}} + \frac{3}{x ^{2}} - 4 x)

\frac{6}{x ^{4}} - \frac{6}{x ^{3}} - 4

Solution steps

\frac{d}{d x} (- \frac{2}{x ^{3}} + \frac{3}{x ^{2}} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{2}{x ^{3}}) + \frac{d}{d x} (\frac{3}{x ^{2}}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

\frac{d}{d x} (4 x) = 4

= - (- \frac{6}{x ^{4}}) - \frac{6}{x ^{3}} - 4

Simplify

= \frac{6}{x ^{4}} - \frac{6}{x ^{3}} - 4

\int cos^{4} (4 x) d x

\frac{\partial}{\partial x} (- 2 e^{- 2 x})

\int a^{2} - z^{2} d z

\frac{\partial}{\partial x} (x e^{x} + 2)

y = (5 x + 2)^{5}

What is the derivative of-2/(x^3+3/(x^2)-4x) ?
The derivative of-2/(x^3+3/(x^2)-4x) is 6/(x^4)-6/(x^3)-4
What is the first derivative of-2/(x^3+3/(x^2)-4x) ?
The first derivative of-2/(x^3+3/(x^2)-4x) is 6/(x^4)-6/(x^3)-4