What is the derivative of 100+0.4x^2 ?

The derivative of 100+0.4x^2 is 0.8x

What is the first derivative of 100+0.4x^2 ?

The first derivative of 100+0.4x^2 is 0.8x

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derivative of

100 + 0.4 x^{2}

0.8 x

Solution steps

\frac{d}{d x} (100 + 0.4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (100) + \frac{d}{d x} (0.4 x^{2})

\frac{d}{d x} (100) = 0

\frac{d}{d x} (0.4 x^{2}) = 0.8 x

= 0 + 0.8 x

Simplify

= 0.8 x

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What is the derivative of 100+0.4x^2 ?
The derivative of 100+0.4x^2 is 0.8x
What is the first derivative of 100+0.4x^2 ?
The first derivative of 100+0.4x^2 is 0.8x