What is the derivative of x^2-3x ?

The derivative of x^2-3x is 2x-3

What is the first derivative of x^2-3x ?

The first derivative of x^2-3x is 2x-3

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derivative of

x^{2} - 3 x

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= 2 x - 3

\frac{d}{d x} (- \frac{( a x + b - d ) ( x ^{2} - 1 )}{x ^{2}})

\frac{d}{d x} (arccsc (\frac{x}{2}))

\frac{d}{d x} (\frac{4 + x}{4 - x})

y^{^{''}} + 4 y = - 12 sin (2 t)

e^{\frac{1}{x}}