What is the derivative of ln(4-x^2) ?

The derivative of ln(4-x^2) is -(2x)/(4-x^2)

What is the first derivative of ln(4-x^2) ?

The first derivative of ln(4-x^2) is -(2x)/(4-x^2)

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derivative of

ln (4 - x^{2})

- \frac{2 x}{4 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (4 - x^{2}))

Apply the chain rule:

\frac{1}{4 - x ^{2}} \frac{d}{d x} (4 - x^{2})

= \frac{1}{4 - x ^{2}} \frac{d}{d x} (4 - x^{2})

\frac{d}{d x} (4 - x^{2}) = - 2 x

= \frac{1}{4 - x ^{2}} (- 2 x)

Simplify

\frac{1}{4 - x ^{2}} (- 2 x) : - \frac{2 x}{4 - x ^{2}}

= - \frac{2 x}{4 - x ^{2}}

x \to 2 lim (\frac{3}{∣ x - 2 ∣})

y d x + (- 2 x - 2 y) d y = 0

3 x^{2} y^{^{'}} = 2 y (y - 3)

\int x e^{(\frac{- x}{2})} d x

\int 8 e^{x} 9 + e^{x} d x

What is the derivative of ln(4-x^2) ?
The derivative of ln(4-x^2) is -(2x)/(4-x^2)
What is the first derivative of ln(4-x^2) ?
The first derivative of ln(4-x^2) is -(2x)/(4-x^2)