What is (\partial}{\partial v}(\frac{v-u)/2) ?

The answer to (\partial}{\partial v}(\frac{v-u)/2) is 1/2

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(\partial}{\partial v}(\frac{v-u)/2)

\frac{\partial}{\partial v} (\frac{v - u}{2})

\frac{1}{2}

Solution steps

\frac{\partial}{\partial v} (\frac{v - u}{2})

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial v} (v - u)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial v} (v) - \frac{\partial}{\partial v} (u))

\frac{\partial}{\partial v} (v) = 1

\frac{\partial}{\partial v} (u) = 0

= \frac{1}{2} (1 - 0)

Simplify

= \frac{1}{2}

x \to + 0 lim (x^{2} \cdot ln (x))

\frac{d}{d x} (12 x^{3} + 4 - ln (3 x + 7))

f (x) = (2 x + 5)^{7}

\int_{2}^{4} (3 x^{2} + \frac{x ^{4}}{4}) d x

f (x) = 7 e^{x} + 5 x, at x = 0

What is (\partial}{\partial v}(\frac{v-u)/2) ?
The answer to (\partial}{\partial v}(\frac{v-u)/2) is 1/2