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Popular >

y^'+2y=e^{-t}

Solution

y^{^{'}} + 2 y = e^{- t}

Solution

y = \frac{1}{e ^{t}} + \frac{c _{1}}{e ^{2 t}}

Solution steps

y^{'} (t) + 2 y = e^{- t}

Solve linear ODE:

y = \frac{1}{e ^{t}} + \frac{c _{1}}{e ^{2 t}}

y = \frac{1}{e ^{t}} + \frac{c _{1}}{e ^{2 t}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=e^{-t} ?
The solution for y^'+2y=e^{-t} is y= 1/(e^t)+(c_{1})/(e^{2t)}