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Popular >

y^'+2y=0

Solution

y^{^{'}} + 2 y = 0

Solution

y = e^{- 2 t + c_{1}}

Solution steps

y^{'} (t) + 2 y = 0

Solve separable ODE:

y = e^{- 2 t + c_{1}}

y = e^{- 2 t + c_{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=0 ?
The solution for y^'+2y=0 is y=e^{-2t+c_{1}}