What is (\partial)/(\partial x)(4x^3y^2-3) ?

The answer to (\partial)/(\partial x)(4x^3y^2-3) is 12x^2y^2

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(\partial)/(\partial x)(4x^3y^2-3)

\frac{\partial}{\partial x} (4 x^{3} y^{2} - 3)

12 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (4 x^{3} y^{2} - 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{3} y^{2}) - \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (4 x^{3} y^{2}) = 12 y^{2} x^{2}

\frac{\partial}{\partial x} (3) = 0

= 12 y^{2} x^{2} - 0

Simplify

= 12 x^{2} y^{2}

\int - 2 + 24 x - 12 x^{2} d x

x x^{2} - 1

x \to 4 - lim (\frac{3 x}{x - 4})

\int 2 x (x^{2} + 7)^{5} d x

(0, 5), (3, - 5)

What is (\partial)/(\partial x)(4x^3y^2-3) ?
The answer to (\partial)/(\partial x)(4x^3y^2-3) is 12x^2y^2