What is the limit as x approaches 3 of | 3/(x^2-9)| ?

The limit as x approaches 3 of | 3/(x^2-9)| is infinity

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limit as x approaches 3 of | 3/(x^2-9)|

x \to 3 lim (\frac{3}{x ^{2} - 9})

\infty

Solution steps

x \to 3 lim (\frac{3}{x ^{2} - 9})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 3 - lim (\frac{3}{x ^{2} - 9}) = \infty

x \to 3 + lim (\frac{3}{x ^{2} - 9}) = \infty

= \infty

f (θ) = 4 tan (θ)

\frac{d}{d x} (2 cos (x) - cos (2 x))

y \cdot ln (x) \cdot \frac{d y}{d x} = (\frac{y + 1}{x})^{2}

\int \frac{1}{2 x ^{2} - 1} d x

y = 7 x + 9 cos (x), (0, 9)

What is the limit as x approaches 3 of | 3/(x^2-9)| ?
The limit as x approaches 3 of | 3/(x^2-9)| is infinity