What is the solution for 7t(dy)/(dt)+y=t^3 ?

The solution for 7t(dy)/(dt)+y=t^3 is y=(t^3)/(22)+(c_{1})/(\sqrt[7]{t)}

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7t(dy)/(dt)+y=t^3

7 t \frac{d y}{d t} + y = t^{3}

y = \frac{t ^{3}}{22} + \frac{c _{1}}{7 t}

Solution steps

7 t \frac{d y}{d t} + y = t^{3}

Solve linear ODE:

y = \frac{t ^{3}}{22} + \frac{c _{1}}{7 t}

y = \frac{t ^{3}}{22} + \frac{c _{1}}{7 t}

\frac{d}{d x} (\frac{x}{x + 8})

\int \frac{ln ( x )}{x 1 + ln ( x ^{2} )} d x

y = ln (x x^{2} - 1)

\frac{d y}{d x} = 2 y - 4

\frac{d}{d x} (8 x^{3} - 8)

What is the solution for 7t(dy)/(dt)+y=t^3 ?
The solution for 7t(dy)/(dt)+y=t^3 is y=(t^3)/(22)+(c_{1})/(\sqrt[7]{t)}