What is the solution for y^'=(13x)/y ?

The solution for y^'=(13x)/y is y=sqrt(13x^2+c_{1)},y=-sqrt(13x^2+c_{1)}

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y^'=(13x)/y

y^{^{'}} = \frac{13 x}{y}

y = 13 x^{2} + c_{1}, y = - 13 x^{2} + c_{1}

Solution steps

y^{'} (x) = \frac{13 x}{y}

Solve separable ODE:

y = 13 x^{2} + c_{1}, y = - 13 x^{2} + c_{1}

y = 13 x^{2} + c_{1}, y = - 13 x^{2} + c_{1}

2 (1 - e^{- 2 t})

lo g_{e} (lo g_{e} (x))

f (x) = x^{4} + 5 x^{2} - x, at x = 1

\frac{d}{d x} (\frac{1 - 4 x}{1 + 4 x})

\int ln (cos (x)) \cdot tan (x) d x

What is the solution for y^'=(13x)/y ?
The solution for y^'=(13x)/y is y=sqrt(13x^2+c_{1)},y=-sqrt(13x^2+c_{1)}