What is the derivative of 4/x-x(x+1) ?

The derivative of 4/x-x(x+1) is -4/(x^2)-2x-1

What is the first derivative of 4/x-x(x+1) ?

The first derivative of 4/x-x(x+1) is -4/(x^2)-2x-1

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\frac{d}{d x} (\frac{4}{x} - x (x + 1))

- \frac{4}{x ^{2}} - 2 x - 1

Solution steps

\frac{d}{d x} (\frac{4}{x} - x (x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{4}{x}) - \frac{d}{d x} (x (x + 1))

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

\frac{d}{d x} (x (x + 1)) = 2 x + 1

= - \frac{4}{x ^{2}} - (2 x + 1)

Simplify

= - \frac{4}{x ^{2}} - 2 x - 1

n = 0 \sum \infty (- \frac{8}{9})^{n}

x^{^{'}} = k x (t)

\int x^{2} + 2 x - 3 d x

x \to - 2 lim (x^{2} + 3)

f (x) = - 2 cos (x), at x = \frac{π}{4}

What is the derivative of 4/x-x(x+1) ?
The derivative of 4/x-x(x+1) is -4/(x^2)-2x-1
What is the first derivative of 4/x-x(x+1) ?
The first derivative of 4/x-x(x+1) is -4/(x^2)-2x-1