What is the integral from-2 to 0 of (7x^2+7x) ?

The integral from-2 to 0 of (7x^2+7x) is 14/3

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integral from-2 to 0 of (7x^2+7x)

\int_{- 2}^{0} (7 x^{2} + 7 x) d x

\frac{14}{3}

Decimal

4.66666 \dots

Solution steps

\int_{- 2}^{0} 7 x^{2} + 7 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} 7 x^{2} d x + \int_{- 2}^{0} 7 x d x

\int_{- 2}^{0} 7 x^{2} d x = \frac{56}{3}

\int_{- 2}^{0} 7 x d x = - 14

= \frac{56}{3} - 14

Simplify

\frac{56}{3} - 14 : \frac{14}{3}

= \frac{14}{3}

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What is the integral from-2 to 0 of (7x^2+7x) ?
The integral from-2 to 0 of (7x^2+7x) is 14/3