What is the derivative of x^2-32sqrt(x) ?

The derivative of x^2-32sqrt(x) is 2x-(16)/(sqrt(x))

What is the first derivative of x^2-32sqrt(x) ?

The first derivative of x^2-32sqrt(x) is 2x-(16)/(sqrt(x))

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\frac{d}{d x} (x^{2} - 32 x)

2 x - \frac{16}{x}

Solution steps

\frac{d}{d x} (x^{2} - 32 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (32 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (32 x) = \frac{16}{x}

= 2 x - \frac{16}{x}

\frac{d}{d x} (\frac{e ^{4 x^{2 + 1}}}{8})

\frac{d}{d x} (f (x) (x)^{- 1})

(x \frac{d y}{d x} + y) (2 (x + x y)) = x y

\frac{x y ^{^{'}}}{y - 2} = y^{2} - y

f (x) = \frac{- 6 x}{x ^{2} + 1}, (1, - 3)

What is the derivative of x^2-32sqrt(x) ?
The derivative of x^2-32sqrt(x) is 2x-(16)/(sqrt(x))
What is the first derivative of x^2-32sqrt(x) ?
The first derivative of x^2-32sqrt(x) is 2x-(16)/(sqrt(x))