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Popular >

y^'=7xe^y,y(0)=0

Solution

y^{^{'}} = 7 x e^{y}, y (0) = 0

Solution

y = - ln (- \frac{7 x ^{2}}{2} + 1)

Solution steps

y^{'} (x) = 7 x e^{y}

Solve separable ODE:

y = - ln (- \frac{7 x ^{2}}{2} + 1)

y = - ln (- \frac{7 x ^{2}}{2} + 1)

Graph

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x \to 0 lim (\frac{8}{x + 2})

(\partial)/(\partial x)(sqrt(x^2+y^2+2))

\frac{\partial}{\partial x} (x^{2} + y^{2} + 2)

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\frac{1}{b - m t}

Frequently Asked Questions (FAQ)

What is the solution for y^'=7xe^y,y(0)=0 ?
The solution for y^'=7xe^y,y(0)=0 is y=-ln(-(7x^2)/2+1)