What is the derivative of x^2+4x+7 ?

The derivative of x^2+4x+7 is 2x+4

What is the first derivative of x^2+4x+7 ?

The first derivative of x^2+4x+7 is 2x+4

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\frac{d}{d x} (x^{2} + 4 x + 7)

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

f (t) = cos^{2} (t)

\frac{d}{d x} (3 x^{2} + 6)

\frac{d}{d x} (2 y sin (x) - x^{3} + ln (y))

\int_{- 1}^{1} e^{- x} d x

f (x) = \frac{1}{( 1 + x ^{2} )}, at x = - 1

What is the derivative of x^2+4x+7 ?
The derivative of x^2+4x+7 is 2x+4
What is the first derivative of x^2+4x+7 ?
The first derivative of x^2+4x+7 is 2x+4